求解三元三次方程组的方法 | 三元三次方程式
֪ʶǰһԪη̸ϵĹϵx1,x2,x3һԪηx3+bx2+cx+d=0...(1)⣬У(x-x1)(x-x2)(x-x3)=0չãx3+(-x1-x2-x3)x2+(x1x2+x1x3+x2x3)x-x1x2x3=0...(2)Ա(1)(2)ʽãx1+x2+x3=-bx1x2+x1x3+x2x3=cx1x2x3=-dڱУx,y,zԿǷ̣x3-0.17177x2+0.00566x-0.0000523182=0....(3)ùʽ÷(3)ǣx1=0.0187115x2=0.0212059x3=0.131853x,y,zx1,x2,x3ϣ6⣺x=0.0187115y=0.0212059z=0.131853x=0.0187115y=0.131853z=0.0212059x=0.0212059y=0.0187115z=0.131853x=0.0212059y=0.131853z=0.0187115x=0.131853y=0.0187115z=0.0212059x=0.131853y=0.0212059z=0.0187115
֪ʶǰһԪη̸ϵĹϵx1,x2,x3һԪη x3+bx2+cx+d=0...(1)⣬У(x-x1)(x-x2)(x-x3)=0չãx3 + (-x1 - x2 - x3) x2+ (x1 x2 + x1 x3 + x2 x3)x - x1 x2 x3 =0...(2)Ա(1)(2)ʽãx1+x2+x3=-bx1x2+x1x3+x2x3=cx1x2x3=-dڱУx,y,zԿǷ̣x3-0.17177x2+0.00566x-0.0000523182=0....(3)ùʽ÷(3)ǣx1=0.0187115x2=0.0212059x3=0.131853x,y,zx1,x2,x3ϣ6⣺x=0.0187115y=0.0212059z=0.131853x=0.0187115y=0.131853z=0.0212059x=0.0212059y=0.0187115z=0.131853x=0.0212059y=0.131853z=0.0187115x=0.131853y=0.0187115z=0.0212059x=0.131853y=0.0212059z=0.0187115